SOLUTION: harry stopped the car at the main entrance.here we are,exactly seven minutes late.he said this time i avereged 30 miles per hour.last time we did the trip we were five minutes ear
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Question 724285: harry stopped the car at the main entrance.here we are,exactly seven minutes late.he said this time i avereged 30 miles per hour.last time we did the trip we were five minutes early.and we sarted at the same time this time i avereged 36 miles per hour. what was the distance? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Here we are, exactly seven minutes late. This time I averaged 30 miles per hour.
Last time we did the trip, we were five minutes early.
We started at the same time. This time I averaged 36 miles per hour.
What was the distance?
:
Since we are using mph:
Change 5 min to 5/60 hr
Change 7 min to 7/60 hr
:
let t = normal "on-time" time for the trip
:
Write a distance equation, dist = speed * time,
36(t-) = 30(t+)
divide both sides by 6
6(t-) = 5(t+)
6t - = 5t +
reduce the fractions
6t - = 5t +
6t - 5t = +
t = hr is the normal travel time
:
Find the distance when 7min late, 67 min
d = 30 * [ + ]
d = 30 * [ + ]
d = 30 *
d =
d = 36 miles
:
Check the distance when 5 min early
d = 36 * [ - ]
d = 36 *
d = 36 miles,
