Question 626102: The question is......Two jets leave at the same time,one is flying eat, the other west. the speed of the jet that is flying west is 75km/h faster than the speed of the jet flying east. in 3 hr they are 3075km apart. let w represent the speed of the plane travelling west and e represent the speed of plane travelling east. you need to know the speed of each plane. write a system of equation to model this situation
Found 2 solutions by mananth, MathTherapy:
Answer by mananth(16949)   (Show Source):
You can put this solution on YOUR website! Plane going East x mph
Plane going West x+ 75 mph
..
They are moving away from each other
So add up their speed.
combined speed = x+x + 75
( 2 x + 75 )
Time = 3 hours
Distance = 3075 miles
Distance = speed * time
(2x+75)*3=3075
6.00 x + 225 = 3075
6 x = 3075 + -225
6 x = 2850
/ 6
x= 475 mph
Plane going East = 475 mph
Plane going West 475 + 75 = 550 mph
m.ananth@hotmail.ca
Answer by MathTherapy(10810)  (Show Source):
You can put this solution on YOUR website!
The question is......Two jets leave at the same time,one is flying eat, the other west. the speed of the jet that is flying
west is 75km/h faster than the speed of the jet flying east. in 3 hr they are 3075km apart. let w represent the speed of the
plane travelling west and e represent the speed of plane travelling east. you need to know the speed of each plane. write a
system of equation to model this situation
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The other "PERSON" totally ignored the given instructions, regarding the assigned variables. It/He/She even came up with a solution,
although one wasn't requested.
As requested, speeds of westbound and eastbound jets are w, and e, respectively
Since the westbound jet is travelling 75 km/h faster than the eastbound, we get the following SPEED equation: w = e + 75 ---- eq (i)
Also, it takes the jets 3 hrs to be 3,075 km apart, at which time, the westbound had travelled "3w" km, and the eastbound, "3e" km,
resulting in the following DISTANCE equation: 3w + 3e = 3,075
3(w + e) = 3(1,025)
w + e = 1,025 --- eq (ii)
w = e + 75 -- eq (i)
The above 2-system equation can be easily solved using SUBSTITUTION.
It can also be solved using ELIMINATION, but written as follows: w - e = 75 ----- eq (i)
w + e = 1,025 -- eq (ii)
That's IT!. That's ALL that's needed.
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