SOLUTION: Hi Town P and town Q are 720km apart.Maggie & Andrew left town P at the same time. The average speed of Andrew was 40km per hour, Maggies was 60km per hour. As soon as they passed

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Hi Town P and town Q are 720km apart.Maggie & Andrew left town P at the same time. The average speed of Andrew was 40km per hour, Maggies was 60km per hour. As soon as they passed      Log On

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Question 1171404: Hi
Town P and town Q are 720km apart.Maggie & Andrew left town P at the same time. The average speed of Andrew was 40km per hour, Maggies was 60km per hour. As soon as they passed Point K which was 1/3 of the total distance,Maggie began to travel at a speed of 80km per hour. Both of them took the same number of hours to travel from town P to town Q.
How long did Maggie take to travel from town P to Point K.
What was Andrews speed from Point K to town Q.
Thanks

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Here is NOT a complete solution:

To reach point K, Maggie went 60 km per hour and distance %281%2F3%29720=240 km. The time taken was 240%2F60=4 hours. Maggie at point K was still 480 k.m. from point Q.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Hi
Town P and town Q are 720km apart.Maggie & Andrew left town P at the same time. The average speed of Andrew was 40km
per hour, Maggies was 60km per hour. As soon as they passed Point K which was 1/3 of the total distance, Maggie began
to travel at a speed of 80km per hour. Both of them took the same number of hours to travel from town P to town Q.

How long did Maggie take to travel from town P to Point K.
What was Andrews speed from Point K to town Q.
Thanks

It’s OBVIOUS that not only did Maggie increase her speed after getting to Point K, but Andrew did, as well.

Distance Maggie covered, from Point P to Point K: 1%2F3 of the 720-km distance: %281%2F3%29720 = 240 kms
Time Maggie took to get to Point K (240 kms): 240%2F60 = 4 hours
Remaining distance Maggie had to go (Point K to Q): 720 - 240 = 480 kms
Time Maggie took to go remaining distance (point K to Q), after increasing speed to 80 km/h: 480%2F80 = 6 hours
Total time Maggie took to get from Point P to Q: 4 + 6 = 10 hours

 
Distance Andrew covered, from Point P to Point K: 1%2F3 of the 720-km distance: %281%2F3%29720 = 240 kms
Time Andrew took to get to Point K (240 kms): 240%2F40 = 6 hours
Remaining distance Andrew had to go (Point K to Q): 720 - 240 = 480 kms
Time Andrew took to go remaining distance (point K to Q), after increasing speed (S): 480%2FS hours
Total time Andrew took to get from Point P to Q: %286+%2B+480%2FS%29 hours 

Since BOTH took the same amount of time to travel from P to Q, then each took 10 hours to complete the trip
We then get: Andrew’s ENTIRE-TRIP time = Maggie’s ENTIRE-TRIP time
                                6+%2B+480%2FS+=+10 
                                3+%2B+240%2FS+=+5 ----- Factoring out GCF, 2, in numerator
                              3S + 240 = 5S ---- Multiplying by LCD, S
                                   240 = 5S - 3S
                                   240 = 2S ===> 2S = 240
     Andrew’s speed from K to Q, or