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An object is dropped from rest at a height of 118 m.
Find the distance it falls during its final second in the air.
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Use the formula for the distance / (the height) at free fall
H =
. (1)
Here H is the height, g is the free fall acceleration, t is the time.
Let's find the time of getting ground for the object dropped from the height of 118 meters.
From formula (1)
t =
=
= 4.9048 seconds (rounded).
One second back is the time 4.9048 - 1 = 3.9048 seconds.
In 3.9048 seconds, the dropped object will fall
h =
= 74.7888 meters.
Hence, in the last second the object will fall
118 - 74.7888 = 43.21 meters, approximately. ANSWER
Solved.