SOLUTION: From a distance 102 mi apart two cars travel toward each other, starting at 10 a.m. one car travels at 45 mph, and the other at 40 mph. At what point between them and at what time
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Question 996986: From a distance 102 mi apart two cars travel toward each other, starting at 10 a.m. one car travels at 45 mph, and the other at 40 mph. At what point between them and at what time do they meet? Found 2 solutions by addingup, MathTherapy:Answer by addingup(3677) (Show Source):
You can put this solution on YOUR website! Let me clarify before I begin that rate is another name for speed.
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Distance= Rate x Time If we divide both sides by rate we get:
Time= Distance/Rate
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Let's call one car A and the other B:
Rate (Speed) of A: 45
Rate (Speed) of B: 40
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Relative Speed:.....85
Distance: 102
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Time: 102/85= 1.2 hours and since there are 60 minutes in 1 hour, .2 of 60 is 60 x .2= 12 minutes.
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The trains meet in 1 hour and 12 minutes. 10 - 1h 12m= 8h 48m
The trains meet at 8h 48m
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How far did they go?
A: 1.2 x 45= 54 miles
B: 1.2 x 40= 48 miles
Proof: 54 + 48= 102 We have the right answer
You can put this solution on YOUR website!
From a distance 102 mi apart two cars travel toward each other, starting at 10 a.m. one car travels at 45 mph, and the other at 40 mph. At what point between them and at what time do they meet?
Distance faster vehicle traveled: miles
Distance slower vehicle traveled: miles
Time vehicles met: 1 hour, 12 minutes after they departed, or at
