SOLUTION: Annette drive to Shawnee in 4 hours and drove back in three hours. What were her speeds of her speed coming back was 11 miles per hour greater that her speed going?

Question 990855: Annette drive to Shawnee in 4 hours and drove back in three hours. What were her speeds of her speed coming back was 11 miles per hour greater that her speed going?
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
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D=distance one way; R=Annette's speed going to Shawnee
R+11mph=speed returning
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4(R)=3(R+11mph)
4R=3R+33mph
R=33mph
ANSWER 1: Her speed going was 33 mph.
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Return speed=R+11mph=33mph+11mph=44mph
ANSWER 2: Her return speed was 44 mph.
.
CHECK:
D=R(4hrs)
D=33mph(4hrs)=132 miles
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D=R+11(3hrs)
132mi=(33mph+11mph)(3hrs)
132mi=(44mph)(3hrs)
132mi=132mi
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