SOLUTION: a jogger runs a distance at a speed of 8 miles per hour and Returns the same distance running at a speed of 6 miles per hour. Find the total distance that the jogger runs if the to

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Question 987095: a jogger runs a distance at a speed of 8 miles per hour and Returns the same distance running at a speed of 6 miles per hour. Find the total distance that the jogger runs if the total time running was one hour forty-five minutes
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
WHICHWAY      speed      time            distance
going          r%5B1%5D       t%5B1%5D           r%5B1%5Dt%5B1%5D
returning      r%5B2%5D       t%5B2%5D           r%5B2%5Dt%5B2%5D
TOTAL                    T


The distance going is the same as the distance returning so you have two equations.
system%28r%5B1%5Dt%5B1%5D=r%5B2%5Dt%5B2%5D%2Ct%5B1%5D%2Bt%5B2%5D=T%29

The unknown variables used are t%5B1%5D and t%5B2%5D for going and returning times, in that order. Solve, and user either direction's distance expression to find the one-way distance.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

a jogger runs a distance at a speed of 8 miles per hour and Returns the same distance running at a speed of 6 miles per hour. Find the total distance that the jogger runs if the total time running was one hour forty-five minutes
Let one-way distance be D
Then time taken to run the distance at 8 mph = D%2F8
Time taken to run the distance at 6 mph = D%2F6
Total time taken for the round-trip: 1 hr, 45 mins, or 1%2645%2F60, or 1%263%2F4. or 7%2F4 hours
We then get: D%2F8+%2B+D%2F6+=+7%2F4++
3D + 4D = 42 -------- Multiplying by LCD, 24
7D = 42
D, or one-way distance = 42%2F7, or 6 miles
Round-trip distance, or total distance traveled: 2(6), or highlight_green%2812%29 miles