SOLUTION: Jane drove to her friend Kim's house 29.1 miles away. As she was leaving her house, she noticed that it was exactly 6 pm. After arriving to Kim's house and spending 1.8 hour there

Algebra.Com
Question 985217: Jane drove to her friend Kim's house 29.1 miles away. As she was leaving her house, she noticed that it was exactly 6 pm.
After arriving to Kim's house and spending 1.8 hour there, she looked at the clock and saw that the time now was 8:45 pm.
What was Jane's average speed on her way to Kim's house?

Answer by macston(5194)   (Show Source): You can put this solution on YOUR website!
.
Total time elapsed from 6:00 PM to 8:45 PM= 2.75 hrs
Time driving=(total time) - (time at Kim's)=2.75hr-1.8hr=0.95hr
.
Average speed=(distance)/(time)=29.1mi/0.95hr=30.6mi/hr
ANSWER: Her average speed was 30.6 MPH.

RELATED QUESTIONS

at 12 pm jane leaves her house and drives north to the beach she arrives at 1:30pm also... (answered by josmiceli)
Aya rode her bicycle from her house to a friend's house, averaging 16 kilometers per... (answered by ankor@dixie-net.com)
Mary left home at 12 noon and drove to visit her mom who lives 20 miles away. After she... (answered by khwang,kiru_khandelwal)
I am being confused with the formula for figuring out the distance and time in this... (answered by stanbon)
Mary left home at 12 noon and drove to visit her mom who lives 20 miles away. After she... (answered by josmiceli)
Teens rode her skateboard to her uncle’s house, 12 miles away. A wheel broke just as she... (answered by ikleyn)
Lois rode her bike to visit a friend. She traveled at 10mi/h. While she was there, it... (answered by askmemath)
Sue took a taxi from her home to her friend’s house. It cost $3.58 per mile and she gave... (answered by advanced_Learner)
Jakia toom 5 hours to get to her parents house her parents house is 300 miles away what... (answered by TimothyLamb)