SOLUTION: Two ships leave the dock at 8:00 am. The first ship travels at a bearing of N 26 degrees W at 18 miles per hour. The second ship travels at a bearing of S 43 degrees W at 24 miles
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-> SOLUTION: Two ships leave the dock at 8:00 am. The first ship travels at a bearing of N 26 degrees W at 18 miles per hour. The second ship travels at a bearing of S 43 degrees W at 24 miles
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Question 977502: Two ships leave the dock at 8:00 am. The first ship travels at a bearing of N 26 degrees W at 18 miles per hour. The second ship travels at a bearing of S 43 degrees W at 24 miles per hours. find the distance between the two ships at 1:00 pm that same day. Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! 0 degrees is due East.
N 26 degrees W would be
S 43 degrees W would be
From 8:00 AM to 1:00 PM would be 5 hours.
So the vector from first ship to the second is,
(,)-(,)=(,)
The distance is the magnitude of the vector,
