SOLUTION: Fred averaged 58 mph on his way to the Rose Bowl. On his way back he traveled at 50 mph but took 64 minutes longer. What was the distance of his route?
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Question 976187: Fred averaged 58 mph on his way to the Rose Bowl. On his way back he traveled at 50 mph but took 64 minutes longer. What was the distance of his route? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Fred averaged 58 mph on his way to the Rose Bowl.
On his way back he traveled at 50 mph but took 64 minutes longer.
What was the distance of his route?
:
Let d = the one-way distance of trip
Since we are dealing in mph, change 64 min to hrs. 64/60 = 1.0667 hrs
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Write a time equation, time = dist/speed
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return time = to time + 64 min (1.0667 hrs) = + 1.0667
multiply by 50*58=2900, cancel the denominators
58d = 50d + 2900(1.0667)
58d - 50d = 3093.43
8d = 3093.43
d = 3093.43
d = 386.68 miles is the one-way distance
:
:
See if that checks out find the actual time each way
386.68/50 = 7.73 hrs
386.68/58 = 6.67
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time differ: 1.06 hrs which is 1.06(60) = 63.6 ~ 64 min
