SOLUTION: A boat goes downstream 72 miles in 3 hours, and travels upstream 60 miles in 6 hours. What is the rate of the river, and what is the boat in still water?

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Question 969896: A boat goes downstream 72 miles in 3 hours, and travels upstream 60 miles in 6 hours.
What is the rate of the river, and what is the boat in still water?

Found 3 solutions by lwsshak3, n2, josgarithmetic:
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
A boat goes downstream 72 miles in 3 hours, and travels upstream 60 miles in 6 hours. What is the rate of the river, and what is the boat in still water?
***
let x=rate of boat in still water
let c= rate of the river
x+c=rate of boat downstream
x-c=rate of boat upstream
travel time*rate=distance
..
3(x+c)=72
6(x-c)=60
..
3x+3c=72
6x-6c=60
..
6x+6c=144
6x-6c=60
add
12x=204
x=17
..
subtract:
12c=84
c=7
rate of boat in still water=17 mph
rate of the river current=7 mph

Answer by n2(91) About Me  (Show Source):
You can put this solution on YOUR website!
.
A boat goes downstream 72 miles in 3 hours, and travels upstream 60 miles in 6 hours.
What is the rate of the river, and what is the boat in still water?
~~~~~~~~~~~~~~~~~~~~~


Looking at the solution by @lwsshak3 in his post, I see that the logic
on how the solution is constructed in the post by @lwsshak3 is the same
which @mananth uses in his solutions to similar problems.

From this fact, I make my conclusion that they both use the same computer code.


Their logic is not effective, and their way solving, in my view, is wrong way teaching.



Answer by josgarithmetic(39835) About Me  (Show Source):
You can put this solution on YOUR website!
speed of the river, r
speed of boat by itself, b

downstream 72%2F3=24
upstream 60%2F6=10

system%28b-r=10%2Cb%2Br=24%29

If add the equations then
2b=34
b=17------boat speed without current

r=-b%2B24
r=24-17
r=7----------river current speed