SOLUTION: IF Adrian Ran 1/2 Mine in 5 Minuets, Carol ran 1/2 mine in 3 minuets,Davon Ran 1/2 mine in 4 minuets and Reena ran 1/2 mine in 6 minuets Whats was there average speed separately (m

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: IF Adrian Ran 1/2 Mine in 5 Minuets, Carol ran 1/2 mine in 3 minuets,Davon Ran 1/2 mine in 4 minuets and Reena ran 1/2 mine in 6 minuets Whats was there average speed separately (m      Log On

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Question 965907: IF Adrian Ran 1/2 Mine in 5 Minuets, Carol ran 1/2 mine in 3 minuets,Davon Ran 1/2 mine in 4 minuets and Reena ran 1/2 mine in 6 minuets Whats was there average speed separately (mph)
Found 2 solutions by josmiceli, Alan3354:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
They want each person's average speed
You have to convert minutes to hours
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Adrian:
+s+=+%28+1%2F2+%29+%2F+%28+5%2F60+%29+
+s+=+%28+1%2F2+%29+%2F+%28+1%2F12+%29+
+s+=+12%2F2+
+s+=+6+ mi/hr
------------------
Carol:
+s+=+%28+1%2F2+%29+%2F+%28+3%2F60+%29+
+s+=+%28+1%2F2+%29+%2F+%28+1%2F20+%29+
+s+=+20%2F2+
+s+=+10+ mi/hr
------------------
Davon:
+s+=+%28+1%2F2+%29+%2F+%28+4%2F60+%29+
+s+=+%28+1%2F2+%29+%2F+%28+1%2F15+%29+
+s+=+15%2F2+
+s+=+7.5+ mi/hr
------------------
Reena:
+s+=+%28+1%2F2+%29+%2F+%28+6%2F60+%29+
+s+=+%28+1%2F2+%29+%2F+%28+1%2F10+%29+
+s+=+10%2F2+
+s+=+5+ mi/hr

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A minuet is a dance, popular a few 100 years ago.
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Maybe you meant minutes?