SOLUTION: A car traveling on an interstate highway leaves a rest stop at 3 p.m., traveling at 75 km/h. Another car leaves the same rest stop 12 min later, headed in the same direction. If

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Question 959278: A car traveling on an interstate highway leaves a rest stop at 3 p.m., traveling at 75 km/h. Another car leaves the same rest stop 12 min later, headed in the same direction. If the second car travels at 195 km/h, how long will it be before it overtakes the first car?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The 1st car has a head start of:
+d%5B1%5D+=+75%2A%2812%2F60%29+
+d%5B1%5D+=+75%2F5+
+d%5B1%5D+=+15+ km
-------------------
Let +d+ = the distance in km the 2nd car
travels until it catches the 1st car
Let +t+ = the time in hrs it takes the
2nd car to catch the 1st car
----------------------------------------
Start a stop watch when the 2nd car leaves
-------------------
Equation for 1st car:
(1) +d+-+15+=+75t+
Equation for 2nd car:
(2) +d+=+195t+
-------------------
By substitution:
(1) +195t+-+15+=+75t+
(1) +120t+=+15+
(1) +t+=+1%2F8+
+%281%2F8%29%2A60+=+7.5+
-------------------
The 2nd car catches the 1st car in 7.5 min
The time would be 3 PM + 12 min + 7.5 min
or 3:19:30 PM
check:
(1) +d+-+15+=+75t+
(1) +d+-+15+=+75%2A%281%2F8%29+
(1) +d+=+9.375+%2B+15+
(1) +d+=+24.375+
and
(2) +d+=+195t+
(2) +d+=+195%2A%281%2F8%29+
(2) +d+=+24.375+
OK