SOLUTION: Function: t(r)=d/r t(hours) d(distance) r(in miles/hour)
reuben drives 10 miles at an initial rate and then drives 20 miles at a rate 5 miles/hour faster than the first rate
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reuben drives 10 miles at an initial rate and then drives 20 miles at a rate 5 miles/hour faster than the first rate
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Question 955088: Function: t(r)=d/r t(hours) d(distance) r(in miles/hour)
reuben drives 10 miles at an initial rate and then drives 20 miles at a rate 5 miles/hour faster than the first rate he drove.
Please help Answer by josgarithmetic(39631) (Show Source):
You can put this solution on YOUR website! The two different rates, each for a different distance, will form two different time expressions, to be summed.
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