SOLUTION: Jane leaves her house and drives in a straight line at a speed of 55 mph. Her speed on the return trip is 65 mph. The trip back home takes 13 minutes less than the outbound trip. W
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Question 950259: Jane leaves her house and drives in a straight line at a speed of 55 mph. Her speed on the return trip is 65 mph. The trip back home takes 13 minutes less than the outbound trip. What was Jane's total travel time in hours? Assume both trips are in a straight line. Give your final answer as a simplified fraction. Found 2 solutions by jhaashok630, lwsshak3:Answer by jhaashok630(18) (Show Source):
You can put this solution on YOUR website!
Jane leaves her house and drives in a straight line at a speed of 55 mph. Her speed on the return trip is 65 mph.
Let x = Distance of her trip
The trip back home takes 13 minutes less than the outbound trip
Time for outbound = x/55
Time for return trip = x/65
equation : x/55-x/65=13/60
x=1859/24 or 77.46
Jane's total travel time in hours = 1859/(24*55) + 1859/(24*55) = 169/60 hours or 169 minutes
You can put this solution on YOUR website! Jane leaves her house and drives in a straight line at a speed of 55 mph. Her speed on the return trip is 65 mph. The trip back home takes 13 minutes less than the outbound trip. What was Jane's total travel time in hours? Assume both trips are in a straight line. Give your final answer as a simplified fraction.
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let x=distance traveled (same for outbound trip and return trip home)
distance/speed=travel time
x/55-x/65=13/60 (trip back home takes 13 minutes less than the outbound trip.) miles
travel time=distance/speed (sum of travel time for both trips)
What was Jane's total travel time in hours? 2.6
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