SOLUTION: Hi, I need help with a word problem: Lucia travels from Point A to Point B at 100 km/hr. Jack leaves at the same times as Lucia, travelling from Point B to Point A at 50 km/hr.

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Question 937727: Hi, I need help with a word problem:
Lucia travels from Point A to Point B at 100 km/hr. Jack leaves at the same times as Lucia, travelling from Point B to Point A at 50 km/hr. The distance from A to B is 100 km. How long after the two leave will they meet on the road?
I have tried to figure out this question for the past hour, but all I know for sure is that Lucia and Jack will meet in less than an hour because the distance from Point A to Point B is 100 km, and Lucia travels at 100 km/hr.
Please reply ASAP :)

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
to make things easy, you can think of this as
one person standing still and the other traveling
at the sum of their speeds from A to B
------------------------------------
Let +t+ = time in hrs until they meet
+100+=+%28+100+%2B+50+%29%2At+
+100+=+150t+
+t+=+100%2F150+
+t+=+2%2F3+
+%282%2F3%29%2A60+=+40+
They will meet in 40 min
-----------------------
check:
Lucia's equation:
+d%5B1%5D+=+100t+
+d%5B1%5D+=+100%2A%282%2F3%29+
+d%5B1%5D+=+200%2F3+
-------------------
Jack's equation:
+d%5B2%5D+=+50t+
+d%5B2%5D+=+50%2A%282%2F3%29+
+d%5B2%5D+=+100%2F3+
------------------
+d%5B1%5D+%2B+d%5B2%5D+=+200%2F3+%2B+100%2F3+
+d%5B1%5D+%2B+d%5B2%5D+=+300%2F3+
+d%5B1%5D+%2B+d%5B2%5D+=+100+
OK