SOLUTION: two cyclists who are 15 km apart start at the same time traveling the same direction. after 6 hours the faster one overtakes the slower one. if they had traveled toward each other,
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Question 932070: two cyclists who are 15 km apart start at the same time traveling the same direction. after 6 hours the faster one overtakes the slower one. if they had traveled toward each other, they would have met after 2 hrs. What is the rate of each cyclist? Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! x = speed of faster biker
y = speed of slower biker
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s = d/t
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relative speed of the bikers traveling in the same direction:
x - y = 15/6
x - y = 2.5 kph
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relative speed of the bikers traveling towards each other:
x + y = 15/2
x + y = 7.5 kph
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put the system of linear equations into standard form
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x - y = 2.5
x + y = 7.5
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copy and paste the above standard form linear equations in to this solver:
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solution:
x = speed of faster biker = 5 kph
y = speed of slower biker = 2.5 kph
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