SOLUTION: May rides her bike the same distance that Leah walks. May rides her bike 10 km/h faster than Leah walks. If it takes May 1 h and Leah 3 h to travel that distance, how fast does e
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-> SOLUTION: May rides her bike the same distance that Leah walks. May rides her bike 10 km/h faster than Leah walks. If it takes May 1 h and Leah 3 h to travel that distance, how fast does e
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Question 928638: May rides her bike the same distance that Leah walks. May rides her bike 10 km/h faster than Leah walks. If it takes May 1 h and Leah 3 h to travel that distance, how fast does each travel Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! x = speed of leah
y = speed of may
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y = x + 10
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s = d/t
d = st
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leah:
d = xt
d = 3x
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may:
d = yt
d = 1y
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equate the distances traveled:
3x = 1y
3x = y
3x = x + 10
2x = 10
x = 5
y = x + 10
y = 5 + 10
y = 15
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answer:
x = speed of leah = 5 kph
y = speed of may = 15 kph
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