SOLUTION: A boat travels 7 km upstream and 7km back. The time for the round trip is 8 hours. The speed of the stream is 4 km/hr. What is the speed of the boat in still water?

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Question 913338: A boat travels 7 km upstream and 7km back. The time for the round trip is 8 hours. The speed of the stream is 4 km/hr. What is the speed of the boat in still water?
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
r*t=d
7/(r-4)+7/(r+4)=8/1
Multiply thru by 1*(r-4)(r+4)
7*1(r+4)+7*1(r-4)=8(r^2-16)
7r+28+7r-28=8r^2-128
r^2-14r-128=0
r=12.2321245982865
Solved by pluggable solver: COMPLETING THE SQUARE solver for quadratics
Read this lesson on completing the square by prince_abubu, if you do not know how to complete the square.
Let's convert 2r%5E2%2B-14r%2B-128=0 to standard form by dividing both sides by 2:
We have: 1r%5E2%2B-7r%2B-64=0. What we want to do now is to change this equation to a complete square %28r%2Bsomenumber%29%5E2+%2B+othernumber. How can we find out values of somenumber and othernumber that would make it work?
Look at %28r%2Bsomenumber%29%5E2: %28r%2Bsomenumber%29%5E2+=+r%5E2%2B2%2Asomenumber%2Ax+%2B+somenumber%5E2. Since the coefficient in our equation 1r%5E2%2Bhighlight_red%28+-7%29+%2A+r%2B-64=0 that goes in front of r is -7, we know that -7=2*somenumber, or somenumber+=+-7%2F2. So, we know that our equation can be rewritten as %28r%2B-7%2F2%29%5E2+%2B+othernumber, and we do not yet know the other number.
We are almost there. Finding the other number is simply a matter of not making too many mistakes. We need to find 'other number' such that %28r%2B-7%2F2%29%5E2+%2B+othernumber is equivalent to our original equation 1r%5E2%2B-7r%2Bhighlight_green%28+-64+%29=0.


The highlighted red part must be equal to -64 (highlighted green part).

-7%5E2%2F4+%2B+othernumber+=+-64, or othernumber+=+-64--7%5E2%2F4+=+-76.25.
So, the equation converts to %28r%2B-7%2F2%29%5E2+%2B+-76.25+=+0, or %28r%2B-7%2F2%29%5E2+=+76.25.

Our equation converted to a square %28r%2B-7%2F2%29%5E2, equated to a number (76.25).

Since the right part 76.25 is greater than zero, there are two solutions:


, or

system%28+%28r%2B-7%2F2%29+=+8.73212459828649%2C+%28r%2B-7%2F2%29+=+-8.73212459828649+%29
system%28+r%2B-7%2F2+=+8.73212459828649%2C+r%2B-7%2F2+=+-8.73212459828649+%29
system%28+r+=+8.73212459828649--7%2F2%2C+r+=+-8.73212459828649--7%2F2+%29

system%28+r+=+12.2321245982865%2C+r+=+-5.23212459828649+%29
Answer: r=12.2321245982865, -5.23212459828649.

Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ar%5E2%2Bbr%2Bc=0 (in our case 2r%5E2%2B-14r%2B-128+=+0) has the following solutons:

r%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-14%29%5E2-4%2A2%2A-128=1220.

Discriminant d=1220 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--14%2B-sqrt%28+1220+%29%29%2F2%5Ca.

r%5B1%5D+=+%28-%28-14%29%2Bsqrt%28+1220+%29%29%2F2%5C2+=+12.2321245982865
r%5B2%5D+=+%28-%28-14%29-sqrt%28+1220+%29%29%2F2%5C2+=+-5.23212459828649

Quadratic expression 2r%5E2%2B-14r%2B-128 can be factored:
2r%5E2%2B-14r%2B-128+=+2%28r-12.2321245982865%29%2A%28r--5.23212459828649%29
Again, the answer is: 12.2321245982865, -5.23212459828649. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+2%2Ax%5E2%2B-14%2Ax%2B-128+%29