Question 899640: A salesperson purchased an automobile that was advertised as averaging 27 mi/gal in the city and 38 mi/gal on the highway. A recent sales trip that covered 1192 miles required 36 gallons of gasoline. Assuming that the advertised mileage estimates were correct, how many miles were driven in the city?
Found 3 solutions by josgarithmetic, richwmiller, MathTherapy:
Answer by josgarithmetic(39617)   (Show Source):
Answer by richwmiller(17219)  (Show Source):
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website! A salesperson purchased an automobile that was advertised as averaging 27 mi/gal in the city and 38 mi/gal on the highway. A recent sales trip that covered 1192 miles required 36 gallons of gasoline. Assuming that the advertised mileage estimates were correct, how many miles were driven in the city?
Let amount of miles driven in the city be D
Then amount of miles driven on highway = 1,192 – D
Equation to be formed:
Miles driven in city, divided by advertised mpg in city, plus miles driven on highway,
divided by advertised mpg on highway, equals total gallons used. This is:
38D + 27(1,192 – D) = 36(27)(38) ------ Multiplying by LCD, 27(38)
38D + 32,184 – 27D = 36,936
38D – 27D = 36,936 – 32,184
11D = 4,752
D, or distance driven in the city =  , or  miles
|
|
|
