SOLUTION: Please help me solve this problem: Two hikers start from the same point and hike in opposite directions around a lake whose shoreline is 11 mi long. One hiker walks 0.5 mph faster

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Question 898520: Please help me solve this problem: Two hikers start from the same point and hike in opposite directions around a lake whose shoreline is 11 mi long. One hiker walks 0.5 mph faster than the other hiker. How fast did each hiker walk if they meet in 2 h?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
The sum of their distances for 2 hours was 11 miles.

RT=D and you have two of these terms for RT.

r = one of their speeds;
r%2A2%2B%28r%2B0.5%29%2A2=11
You know what to do.

Solution steps could vary, but one might choose:
2%28r%2B%28r%2B1%2F2%29%29=11
2%28r%2Br%2B1%2F2%29=11
2%282r%2B1%2F2%29=11
Continue this until finished........

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Please help me solve this problem: Two hikers start from the same point and hike in opposite directions around a lake whose shoreline is 11 mi long. One hiker walks 0.5 mph faster than the other hiker. How fast did each hiker walk if they meet in 2 h?


Let speed of slower hiker be S

Then speed of faster hiker is: S + .5

Since their respective distances sum to 11 miles, and they met in 2 hours, then we get: 

2S + 2(S + .5) = 11

2S + 2S + 1 = 11

4S = 11 – 1

4S = 10

S, or speed of slower hiker = 10%2F4, or highlight_green%28highlight_green%282.5%29%29 mph

Faster hiker’s speed: 2.5 + .5, or highlight_green%28highlight_green%283%29%29 mph

You can do the check!! 



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Further help is available, online or in-person, for a fee, obviously. 



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