SOLUTION: a car travelling at 108km/hour has its speed reduced to 36 km/hour while travelling a distance of 200 m .then what is accelaration and time taken are ????????????????????????

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Question 884287: a car travelling at 108km/hour has its speed reduced to 36 km/hour while travelling a distance of 200 m .then what is accelaration and time taken are ????????????????????????
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Acceleration based on initial and final velocity and distance traveled.
a=%28v%5Bf%5D%5E2-v%5Bi%5D%5E2%29%2Fs
Convert velocities to m%2Fs
108km%2Fhr*1000%2F3600%28m%2Fkm%29%28hr%2Fsec%29=30m%2Fs
36km%2Fhr*1000%2F3600%28m%2Fkm%29%28hr%2Fsec%29=10m%2Fs
a=%28v%5Bf%5D%5E2-v%5Bi%5D%5E2%29%2Fs
a=%2810%5E2-30%5E2%29%2F200=%28100-900%29%2F200=-800%2F200=-4m%2Fs%5E2
.
.
.
Final velocity given initial velocity, acceleration, and time.
v%5Bf%5D=v%5Bii%5D%2Bat
10=40-4t
-4t=-30
t=30%2F4=15%2F2sec