SOLUTION: George and Bill left town A for town B at the same time. George was riding a bicycle at a constant speed, while Bill was driving a car. Bill traveled 5 times faster than George. Bi

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Question 857726: George and Bill left town A for town B at the same time. George was riding a bicycle at a constant speed, while Bill was driving a car. Bill traveled 5 times faster than George. Bill’s car broke halfway, and the rest of the way to the town B Bill traveled by foot with a speed equal to half of the George’s bicycle speed. Who got to B first: George or Bill
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
George and Bill left town A for town B at the same time.
George was riding a bicycle at a constant speed, while Bill was driving a car.
Bill traveled 5 times faster than George. Bill’s car broke halfway, and the rest of the way to the town B Bill traveled by foot with a speed equal to half of the George’s bicycle speed.
Who got to B first: George or Bill
:
Let s = G's bilking speed
then
5s = B's driving speed
and
.5s = B's walking speed
;
Let d = the distance from A to B
:
Write a time equation; time = dist/speed
Find the difference in their travel time (t)
dif = B's drive time + B's walk time - G's bike time
t = %28.5d%29%2F%285s%29 + %28.5d%29%2F%28.5s%29 - d%2Fs
Use 5s as the common denominator
t = %28.5d%29%2F%285s%29 + %285d%29%2F%285s%29 - %285d%29%2F%285s%29
t = %285.5d%29%2F%285s%29%7B%7B%7B+-+%7B%7B%7B%285d%29%2F%285s%29
t = %28.5d%29%2F%285s%29 is the time difference, if we got a neg value then B would be getting there first