Question 857407: Driver 1 moves at 70mph. Driver 2 moves at 97mph
Driver 2 starts 2 minutes after Driver 1
How long will it take driver 2 to catch up? Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! In two minutes driver 1 goes 2/60*70= 7/3=2 1/3 miles
Driver 2 goes 27 mph faster than driver 1
27*t=7/3*60
t = 140/27
t = 5.1852 minutes which is a little more than 5 minutes and 11 second