SOLUTION: A train leaves Albert Lea, MN headed due north towards Brainerd, MN at 12:00 noon traveling at 50 mph. One hour later, at 1pm, a train leaves Brainerd traveling toward Albert Lea
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: A train leaves Albert Lea, MN headed due north towards Brainerd, MN at 12:00 noon traveling at 50 mph. One hour later, at 1pm, a train leaves Brainerd traveling toward Albert Lea
Log On
Question 837606: A train leaves Albert Lea, MN headed due north towards Brainerd, MN at 12:00 noon traveling at 50 mph. One hour later, at 1pm, a train leaves Brainerd traveling toward Albert Lea 215 miles away at 60 mph. At what time do the trains meet? Answer by josgarithmetic(39618) (Show Source):
You can put this solution on YOUR website! A to B, and B to A, two different trains, meet in the middle, different departure times. The wording is a little oddly organized, but the total distance traveled will be the distance between A and B, which is 215 miles. This is given in the last sentence of the description.
___________speed_____________time_________distance
A to B______50________________t+1
B to A______60_________________t
Total_______________________________________215
Find the distance expressions using rate*time=distance.
___________speed_____________time_________distance
A to B______50________________t+1___________50(t+1)
B to A______60_________________t____________60t
Total_______________________________________215
Total distances make for the equation to solve for t,
-
This is , corresponding to 2:30PM.
(