SOLUTION: A baseball is thrown with a vertical velocity of 50 ft/s from an initial height of 6 ft. The height h in feet of the baseball can be modeled by h(t) = -16t^2 + 50t + 6, where t is

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: A baseball is thrown with a vertical velocity of 50 ft/s from an initial height of 6 ft. The height h in feet of the baseball can be modeled by h(t) = -16t^2 + 50t + 6, where t is       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 818488: A baseball is thrown with a vertical velocity of 50 ft/s from an initial height of 6 ft. The height h in feet of the baseball can be modeled by h(t) = -16t^2 + 50t + 6, where t is the time in seconds since the ball was thrown. It takes the ball approximately _____ seconds to reach its maximum height.
what is the maximum height that the ball reaches?
The maximum height reached by the ball is _____ feet.
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
h(t) = -16t^2 + 50t + 6

Extreme values of a parabola occur at the vertex, so 
the vertex formula:

The t-coordinate is found by the formula -b%2F%282a%29

-b%2F%282a%29 = -%2850%29%2F%282%28-16%29%29 = 25%2F16 or 1.5625 seconds.

That's the answer you were asked to find.


The h-coordinate is found by substituting the t-value
into the formula

h(t) = -16t^2 + 50t + 6

h%2825%2F16%29 = -16%2825%2F16%29%5E2 + 50%2825%2F16%29 + 6

the answer is 59.125 feet.  That's the highest point it reaches,
and it reaches that in 1.5625 seconds.

Edwin