Question 818262: Hartford,Connecticut and Topeka, Kansas are roughly 1260 miles apart. If it took 3 hours and 20 minutes for a plane to fly into the wind from Hartford to Topeka, and 2 hours for a plane to make the return trip with the wind, what was the air speed of the plane and what was the speed of the wind??
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! s = d / t
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outbound:
s - w = 1260/(3+1/3)
s - w = 1260/(10/3)
s - w = 378
s = 378 + w
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return:
s + w = 1260/2
s + w = 630
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s + w = 630
378 + w + w = 630
378 + 2w = 630
2w = 252
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w = 126 mph
s = 504 mph
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