Question 816638: A boat takes 2/3 as much time to travel downstream as to return. If the rate of the river's current is 8 kph, what is the rate of the boat in still water?
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! time to return: t
time to go: (2/3)t
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w = 8 kph
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s = d / t
d = s * t
D = trip distance one way
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D = (b + w)(2/3)t
D = (b - w)t
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(b + w)(2/3)t = (b - w)t
(b + w)(2/3) = (b - w)
(2/3)b + (2/3)w = b - w
(2/3)w + (3/3)w = (3/3)b - (2/3)b
(5/3)w = (1/3)b
b = 3(5/3)8
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b = 40 kph
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