SOLUTION: The vessel sailed San Francisco USA ZD+8h at 2330h LT 29 August for Manila ZD-8h with a speed of 15Kts total distance is 6250 Miles Find: 1) ETA MANILA IN GMT AND DATE

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Question 800991: The vessel sailed San Francisco USA ZD+8h at 2330h LT 29 August for Manila ZD-8h with a speed of 15Kts total distance is 6250 Miles
Find: 1) ETA MANILA IN GMT AND DATE
2) ETA MANILA IN LMT AND DATE
After sailing 3300 Miles the captain decide to arrive 36h earlier from his original ETA.
Find: 1) Speed
Answer by Finavon(81) About Me  (Show Source):
You can put this solution on YOUR website!
Departs (GMT) 29/8 23:30 +8:00 = 30/8 07:30
Duration: 6250/15 = 416.66 hrs = 416/24 days + 40 min = 17 days 8 hrs 40 min
Expected arrival (GMT) 17/9 16:10
(LT) 18/9 00:10
Remaining distance = 6250 - 3330 = 2920 miles
speed=distance/time so time= distance/speed
original 2920/15
new 2920/S
+2920%2F15+-+36+=+2920%2FS+
+%282920-15%2A36%29%2F15+=+2920%2FS+
+S+=+2920%2F%282920-540%29%2A15+=+18.4
New speed is 18.4 kt