SOLUTION: A motorcycle breaks down and the rider has to walk the rest of the way to work. The motorcycle was traveling at 45mph, and the rider walks at the speed of 6mph. The distance betwee
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Question 76448This question is from textbook Algebra 1
: A motorcycle breaks down and the rider has to walk the rest of the way to work. The motorcycle was traveling at 45mph, and the rider walks at the speed of 6mph. The distance between home and work is 25mi and the total time for the trip was 2 hours. How far did the motorcycle go before it broke down? This question is from textbook Algebra 1
You can put this solution on YOUR website! A motorcycle breaks down and the rider has to walk the rest of the way to work. The motorcycle was traveling at 45mph, and the rider walks at the speed of 6 mph. The distance between home and work is 25 mi and the total time for the trip was 2 hours. How far did the motorcycle go before it broke down?
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Let d = distance traveled by the motorcycle
(25-d) = distance he walked
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Write a time equation; Time = distance/speed
:
Riding time + walking time = 2 hrs + = 2
:
Multiply equation by 90 to get rid of the denominators:
2d + 15(25-d) = 90(2)
2d + 375 - 15d = 180
2d - 15d = 180 - 375
-13d = -195
d = -195/-13
d = 15 miles he rode
:
:
Check: 25 - 15 = 10 mi he walked
15/45 + 10/6 =
1/3 + 5/3 = 6/3 = 2 hrs
