SOLUTION: Susan leaves home at 8am, driving to a friend's cabin. Her sister, Carol, leaves home an hour later also driving to the cabin. By driving 7 mph faster than Susan, Carol overtakes S
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Question 741511: Susan leaves home at 8am, driving to a friend's cabin. Her sister, Carol, leaves home an hour later also driving to the cabin. By driving 7 mph faster than Susan, Carol overtakes Susan at 2pm.
What was the average speed of each sister?
How far do they drive before Carol overtakes Susan?
Please show work, if you have to.
Thank you Answer by solver91311(24713) (Show Source):
From 8 am to 2 pm is 6 hours, so Susan drove at miles per hour for 6 hours and therefore travelled miles. Carol only drove for 5 hours, because she left one hour later. But she travelled at miles per hour, so she travelled miles. Those two distances have to be equal, so set them equal and solve for . Once you know , Susan's speed, you can add 7 to get Carol's speed. Calculate to get the distance traveled. Then calculate to check your work.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
