SOLUTION: How far from an airport can an airplane fly and return in 8 hours, if its outgoing speed is 160 kilometers per hour and its returning speed is 240 kilometers per hour?

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Question 735210: How far from an airport can an airplane fly and return in 8 hours, if its outgoing speed is 160 kilometers per hour and its returning speed is 240 kilometers per hour?
Found 4 solutions by lynnlo, ikleyn, greenestamps, josgarithmetic:
Answer by lynnlo(4176) About Me  (Show Source):
Answer by ikleyn(53763) About Me  (Show Source):
You can put this solution on YOUR website!
.
How far from an airport can an airplane fly and return in 8 hours, if its outgoing speed is 160 kilometers per hour
and its returning speed is 240 kilometers per hour?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Let's 'd' be this unknown distance to fly from the airport, in kilometers.


Then the time to fly out is      d%2F160  hours;

     the time to return back is  d%2F240  hours,

and the sum of these two pieces of time is 8 hours


    d%2F160 + d%2F240 = 8.


It is your equation to find 'd'.


To find it, multiply all the terms by the least common denominator, which is 480.
You will get

    3d + 2d = 8*480,

      5d    = 3840,

       d    = 3840/5 = 768 kilometers.


ANSWER.  The distance to fly from the airport is 768 kilometers.

Solved.



Answer by greenestamps(13334) About Me  (Show Source):
You can put this solution on YOUR website!


Here is a very different solution method than the one shown by the other tutor.

The ratio of the two speeds is 160:240 = 2:3; since the distances out and back are the same, the ratio of the times at the two speeds is 3:2. That means 3/5 of the time is at the lower speed and 2/5 is at the higher speed.

The total time is 8 hours; 3/5 of that total time is 24/5 hours, or 4 4/5 hours.

Flying at 160 km/h for 4 4/5 hours, the plane can fly (160)(24/5) = 32*24 = 768 km.

To check that answer, we can find that the distance the plane flies at 240 km/h for 16/5 hours is (240)(16/5) = 48*16 = 768 km.

ANSWER: 768 km


Answer by josgarithmetic(39799) About Me  (Show Source):
You can put this solution on YOUR website!
How far out to go,  d

                    SPEED        TIME        DISTANCE
GOING OUT            160         d/160         d
RETURNING            240         d/240         d
SUM                               8

d%2F160%2Bd%2F240=8


STEPS--------------
Finding smallest denominator to use
2*2*2*2*2*5 and 2*3*2*2*2*5
2^5*5 and 2^4*3*5
common denominator should be 2^5*3*5=480

%283%2F3%29%28d%2F160%29%2B%282%2F2%29%28d%2F240%29=8
3d%2F480%2B2d%2F480=8
5d%2F480=8
d%2F96=8
d=96%2A8
highlight%28d=768%29