SOLUTION: Please help! Thank you in advance!
Two ships A and B start from the same port at 8am. Ship A heads north 62 degrees 15 minutes east with a speed of 12 km/hr. Ship B takes the c
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Two ships A and B start from the same port at 8am. Ship A heads north 62 degrees 15 minutes east with a speed of 12 km/hr. Ship B takes the c
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Question 723868: Please help! Thank you in advance!
Two ships A and B start from the same port at 8am. Ship A heads north 62 degrees 15 minutes east with a speed of 12 km/hr. Ship B takes the course of north 48 degrees 20 minutes west with the speed of 16 km/hr. How far apart are they at 10:45am? What is the bearing of B from A? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Two ships A and B start from the same port at 8am. Ship A heads north 62 degrees 15 minutes east with a speed of 12 km/hr. Ship B takes the course of north 48 degrees 20 minutes west with the speed of 16 km/hr. How far apart are they at 10:45am? What is the bearing of B from A?
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Draw the picture.
Distance for A = side A = rate*time = 12*2.75 = 30 km
Distance for B = side B = rate*time = 16*2.75 = 40 km
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Angle made by the two sides = C = 62.25+48.33 = 110.58 degrees
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Solve for side "c" using the Law of Cosines.
c^2 = a^2 + b^2-2ab*cos(C)
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c = sqrt(3343.63) = 57.82 km
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Bearing of B from A = 110.58 degrees
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Cheers,
Stan H
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