SOLUTION: A projectile is launched from the ground with an initial velocity of V0 feet per second. Neglecting air resistance, its height in feet per seconds after launch is given by s = -16t
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Question 708281: A projectile is launched from the ground with an initial velocity of V0 feet per second. Neglecting air resistance, its height in feet per seconds after launch is given by s = -16t^2 +V0t. Find the time(s) that the projectile will
(a) reach a height of 240ft and
(b) return to the ground when V0= 128 feet per second. Answer by solver91311(24713) (Show Source):
Substitute your given value of and then solve the quadratic. The equation will have two zeros, one representing the time the projectile reaches 240 feet on the way up, and the other representing the time the projectile passes 240 feet again on the way back down.
(b) Same as part (a) except you set the function equal to the height of the ground, i.e. zero. Your two zeros will be zero and some positive number. The zero root represents the instant of launch, and the other is the time of return to ground.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
