SOLUTION: A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function h(t)=80t+16t^2 . What is the maximum height that the ball will reach?
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Question 677480: A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function h(t)=80t+16t^2 . What is the maximum height that the ball will reach?
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Height= ? feet Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function h(t)=80t+16t^2 . What is the maximum height that the ball will reach?
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h(t) increases with t, there's no max.
It goes up, never comes down.
