SOLUTION: A truck leaves the dock at 10:00 am going 69 miles per hour. A second truck leaves two hours later going 82 mph. At what time will the two trucks meet up

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Question 659306: A truck leaves the dock at 10:00 am going 69 miles per hour. A second truck leaves two hours later going 82 mph. At what time will the two trucks meet up
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The 1st truck has a head start of
+d%5B1%5D+=+69%2A2+
+d%5B1%5D+=+138+ mi
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Now start a stopwatch when the 2nd truck leaves
Both trucks will travel for the same amount
of time until they meet
Let +d+ = distance 2nd truck travels
Let +t+ = time on stopwatch
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1st truck's equation:
+d+-+138+=+69t+
2nd truck's equation:
+d+=+82t+
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+d+=+69t+%2B+138+
By substitution:
+82t+=+69t+%2B+138+
+13t+=+138+
+t+=+10.6154+ hrs
+.6154%2A60+=+36.9231+
+.9231%2A60+=+55.4+
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10 hrs 36 min and 55 sec is the time elapsed
after 10 AM + 2 hrs or 12 PM
They will meet at 10:36:55 PM