SOLUTION: Can you show me the steps to solving this and how to set up an equation to solve it? Sarah and John are driving in opposite direction on a straight road. John is driving fifteen m

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Question 644568: Can you show me the steps to solving this and how to set up an equation to solve it?
Sarah and John are driving in opposite direction on a straight road. John is driving fifteen miles per hour faster than Sarah. After three hours they are 375 miles apart. How fast were Sarah and John traveling?

Found 2 solutions by josmiceli, stanbon:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
With this type of problem, I like to think of
one of them standing still and the other one
moving at the sum of their speeds
Let Sarah's speed = +s+ mi/hr
John's speed = +s+%2B+15+ mi/hr
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The equation of motion is
+375+=+%28+s+%2B+s+%2B+15+%29%2A3+
+375+=+%28+2s+%2B+15+%29%2A3+
+375+=+6s+%2B+45+
+6s+=+330+
+s+=+55+
+s+%2B+15+=+70+
Sarah is traveling at 55 mi/hr
John is traveling at 70 mi/hr
check answer:
Sarah's distance = +55%2A3+
+55%2A3+=+165+ mi
John's distance = +70%2A3+
+70%2A3+=+210+ mi
+165+%2B+210+=+375+ as it should
OK

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Sarah and John are driving in opposite direction on a straight road. John is driving fifteen miles per hour faster than Sarah. After three hours they are 375 miles apart. How fast were Sarah and John traveling?
----
You want to solve for "rate".
----
Sarah DATA:
rate = x mph ; time = 3 hours ; distance = 3x miles
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John DATA:
rate = x+15 mph ; time = 3 hours ; distance = 3(x+15) miles
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Equation:
distance + distance = 375 miles
3x + 3(x+15) = 375
3x + 3x + 45 = 375
6x = 330
x = 55 mph (Sarah's rate)
x+15 = 70 mph (John's rate)
==========================
Cheers,
Stan H.
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