SOLUTION: A boy leaves a town at noon on a bicycle traveling west at rate of 15 mph at 4pm. A girl leaves town in a car in the same direction at the rate of 45 mph.How many hours will it tak
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-> SOLUTION: A boy leaves a town at noon on a bicycle traveling west at rate of 15 mph at 4pm. A girl leaves town in a car in the same direction at the rate of 45 mph.How many hours will it tak
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Question 628313: A boy leaves a town at noon on a bicycle traveling west at rate of 15 mph at 4pm. A girl leaves town in a car in the same direction at the rate of 45 mph.How many hours will it take to watch a boy and What time? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A boy leaves a town at noon on a bicycle traveling west at rate of 15 mph.
At 4pm a girl leaves town in a car in the same direction at the rate of
45 mph.
How many hours will it take to catch the boy and What time?
:
Let t = travel time of the girl in the car
then
(t+4) = travel time of the boy on the bike (left 4 hrs earlier)
:
When the girl catches the boy, they will have traveled the same distance
Write a distance equation; dist = speed * time
:
45t = 15(t+4)
45t = 15t + 60
45t - 15t = 60
30t = 60
t = 60/30
t = 2 hrs travel time of the girl in the car to catch the boy on the bike
She left at 4 PM, therefore time of catch = 6 PM
:
:
Confirm our solution by finding the distance of each, should be equal
45(2) = 90 mi
15(2+4) = 90 mi
