Question 618992: A frog is sitting on a stump 6 feet above the ground. It hops off the stump and lands on the ground 4 feet away. During its leap, its height "h" is given by the equation h=-.5+.5x+6 where "x" is the distance in feet from the base of the stump, and "h" is height in feet. How far was the frog from the base of the stump when it was 2.75 feet above the ground?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A frog is sitting on a stump 6 feet above the ground. It hops off the stump and lands on the ground 4 feet away. During its leap, its height "h" is given by the equation h=-.5x^2 +.5x+6 where "x" is the distance in feet from the base of the stump, and "h" is height in feet. How far was the frog from the base of the stump when it was 2.75 feet above the ground?
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Solve:
-0.5x^2 + 0.5x + 6 = 2.75
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-0.5x^2 + 0.5x + 3.25 = 0
x = 3.098 ft.
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Cheers,
Stan H.
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