SOLUTION: Two cyclists, 48 miles apart, start riding toward each other at the same time. One cycles 3 times as fast as the other. If they meet 2 hours later, what is the speed (in mi/h) of t
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: Two cyclists, 48 miles apart, start riding toward each other at the same time. One cycles 3 times as fast as the other. If they meet 2 hours later, what is the speed (in mi/h) of t
Log On
Question 569506: Two cyclists, 48 miles apart, start riding toward each other at the same time. One cycles 3 times as fast as the other. If they meet 2 hours later, what is the speed (in mi/h) of the faster cyclist? Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! They are approaching each other at the sum of their speeds
Think of one ( either one ) as standing still and the
other moving at the sum of their speeds
Call the speed of the faster one
The speed of the slower one is
I can say
The speed of the faster cyclist is 18 mi/hr
