SOLUTION: Hi, this has me stumped:
Two drivers 240 miles apart start toward each other at 2pm. The faster one averages 50 mph and the slower one averages 35mph. The faster one stops for 2 h
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Two drivers 240 miles apart start toward each other at 2pm. The faster one averages 50 mph and the slower one averages 35mph. The faster one stops for 2 h
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Question 522219: Hi, this has me stumped:
Two drivers 240 miles apart start toward each other at 2pm. The faster one averages 50 mph and the slower one averages 35mph. The faster one stops for 2 hours along the way before they pass each other.
Write the equation to determine how long it will take them before they pass each other.
I cant sort out how to express the 2 hours of not traveling... this is what I have so far: 240-35t= 50*(4.8-2.0)
Above, I'm not sure if I should be subtracting 2 or adding 2 or if that equation is even right :/ Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Two drivers 240 miles apart start toward each other at 2pm.
The faster one averages 50 mph and the slower one averages 35mph.
The faster one stops for 2 hours along the way before they pass each other.
Write the equation to determine how long it will take them before they pass each other.
:
Let t = travel time of the slower car
then
(t-2) = travel time of the faster
:
When they do pass each other the sum of their travel distances = 240
Write a dist equation: dist = speed * time
:
fast car dist + slow car dist = 240 mi
50(t-2) + 35t = 240
