SOLUTION: At 9:30 am Andrew left Exeter for Portsmouth cycling at 12mi/hr. At 10 am Stacey left Portsmouth for Exeter cycling at 16mi/hr. The distance from Exeter to Portsmouth is 20 miles.

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: At 9:30 am Andrew left Exeter for Portsmouth cycling at 12mi/hr. At 10 am Stacey left Portsmouth for Exeter cycling at 16mi/hr. The distance from Exeter to Portsmouth is 20 miles.       Log On

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Question 514902: At 9:30 am Andrew left Exeter for Portsmouth cycling at 12mi/hr. At 10 am Stacey left Portsmouth for Exeter cycling at 16mi/hr. The distance from Exeter to Portsmouth is 20 miles. Find the times when they met?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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At 9:30 am Andrew left Exeter for Portsmouth cycling at 12mi/hr.
At 10 am Stacey left Portsmouth for Exeter cycling at 16mi/hr.
The distance from Exeter to Portsmouth is 20 miles.
Find the times when they met?
:
Let t = Stacey's travel time
then
(t+.5) = Andrew's travel time (started a half hr earlier than Stacey)
:
When S overtakes A they will have traveled the same distance.
:
Write a distance equation; dist = speed * time
:
S's dist = A's dist
16t = 12(t+.5)
16t = 12t + 6
16t - 12t = 6
4t = 6
t = 6%2F4
t = 1.5 hrs, S's travel time who started at 10:00, therefore
10:00 + 1:30 = 11:30 AM when S overtakes A
:
:
:
Confirm this by finding the actual distance each traveled, they should be equal.
A: 12(1.5 + .5) = 24 km
S: 16(1.5) = 24 km