SOLUTION: 2 children are balanced on a seesaw. One of them weighing 40 lbs is 6 feet from the fulcrum. How far from the fulcrum on the other side must the other child sit if he weighs 60 lbs
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Question 488890: 2 children are balanced on a seesaw. One of them weighing 40 lbs is 6 feet from the fulcrum. How far from the fulcrum on the other side must the other child sit if he weighs 60 lbs?
You can put this solution on YOUR website! 2 children are balanced on a seesaw. One of them weighing 40 lbs is 6 feet from the fulcrum. How far from the fulcrum on the other side must the other child sit if he weighs 60 lbs?
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Equation:
40*6 = 60x
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x = (40*6)/60
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x = 40/10
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x = 4 ft.
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Cheers,
Stan H.