SOLUTION: A long distance trucker traveled 180 miles in one direction during a snow storm. The return trip in rainy weather was accompolished at double spped and took 3 hours less time. Find

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Question 488673: A long distance trucker traveled 180 miles in one direction during a snow storm. The return trip in rainy weather was accompolished at double spped and took 3 hours less time. Find the speed going?
The speed going was ____mph
Found 2 solutions by stanbon, MathTherapy:
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
A long distance trucker traveled 180 miles in one direction
during a snow storm.
--------------------
The return trip in rainy weather was accomplished at double speed and took 3 hours less time. Find the speed going?
---
Going DATA:
distance = 120 miles ; rate = x mph ; time = d/r = 180/x hrs
===================
Return DATA:
distance = 120 miles ; rate = 2x mph ; time = 120/(2x) = 60/x hrs
===================
Equation:
time - time = 3 hrs
180/x - 60/x = 3 hrs
----
180 - 60 = 3x
3x = 120
x = 40 mph (the "Going" rate)
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Cheers,
Stan H.

The speed going was ____mph

Answer by MathTherapy(10551) (Show Source):
You can put this solution on YOUR website!
A long distance trucker traveled 180 miles in one direction during a snow storm. The return trip in rainy weather was accompolished at double spped and took 3 hours less time. Find the speed going?
The speed going was ____mph

Let the trucker�s speed in the snow storm be S
Then time taken to do the trip in the snow storm = 180/S

The trucker�s speed on the return trip = 2S (double the speed in the snow storm)
Then the time taken to do the return trip = 180/2S, or 90/S

Since the trip in the snow storm took longer than the trip in the rain, then we can say that:

180/S � 3 = 90/S
180 � 3S = 90 ------- Multiplying by LCD, S
� 3S = - 90

S, or speed in snow storm = or

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