SOLUTION: Hi, my question is this
Two aircraft both depart from the same airport at different times. The 1st takes off at 14:00 (2pm) and maintains a speed of 180km/h. The second takes of
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Two aircraft both depart from the same airport at different times. The 1st takes off at 14:00 (2pm) and maintains a speed of 180km/h. The second takes of
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Question 454308: Hi, my question is this
Two aircraft both depart from the same airport at different times. The 1st takes off at 14:00 (2pm) and maintains a speed of 180km/h. The second takes off at 19:00 (7pm) and travels at 480km/h. By which time will the second aircraft catch up with the first?
Thought I was a whizz at Speed/Distance/Time calculation but this one took me by suprise. The answer in Laymans terms and Algebra would be vastly appreciated! Answer by htmentor(1343) (Show Source):
You can put this solution on YOUR website! Two aircraft both depart from the same airport at different times. The 1st takes off at 14:00 (2pm) and maintains a speed of 180km/h. The second takes off at 19:00 (7pm) and travels at 480km/h. By which time will the second aircraft catch up with the first?
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The 1st plane has a head start of 180 km/h * 5 h = 900 km
The RELATIVE speed of the two planes is 480 km/h - 180 km/h = 300 km/h
This is as if plane 1 were standing still and plane 2 approached it at 300 km/h.
So the time required to travel the 900 km is:
t = d/v = 900 km/300 km/h = 3 h
Therefore, the time will be 7 pm + 3 h = 10 pm
