SOLUTION: Palmer's average running speed is 3 Kilometers per hour faster than his walking speed. If Palmer can run around a 20-Kilometer course in 2 hours, how many hourse would it take her
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Question 446364: Palmer's average running speed is 3 Kilometers per hour faster than his walking speed. If Palmer can run around a 20-Kilometer course in 2 hours, how many hourse would it take her Palmer to walk the same course?
I NEED TO SEE THE WORK ON HOW YOU GOT THE ANSWER!! Found 3 solutions by mananth, ikleyn, josgarithmetic:Answer by mananth(16949) (Show Source):
You can put this solution on YOUR website! walking speed =x
running speed = x+3
d=rt
20=(x+3)*2
20=2x+6
20-6=2x
14=2x
x=7 kmph running speed
so walking speed = 4 kmph (7-3)
d=rt
d=20
r=4
20=4*t
20/4=t
t= 5 hours walking time for 20 km
You can put this solution on YOUR website! .
Palmer's average running speed is 3 Kilometers per hour faster than his walking speed.
If Palmer can run around a 20-Kilometer course in 2 hours, how many hours would it take for Palmer to walk the same course?
I NEED TO SEE THE WORK ON HOW YOU GOT THE ANSWER!!
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(1) The solution in the post by @mananth is ABSOLUTELY WRONG.
(2) This problem is PRIMITIVE at the level of 4th or 5th grade student: it is not an Algrbra
or a Pre-algebra problem - - - it is an Arithmetic problem.
Step by step solution
(1) the running speed is = 10 kilometers per hour, or 10 km/h.
(2) The walking speed is 3 km/h slower, so the walking speed is 10-3 = 7 km/h.
(3) Hence, the time for Palmer to walk the 20 km course is = 2 hours.
ANSWER. The time for Palmer to walk the course is 2 hours, under given conditions.
You can put this solution on YOUR website! Run speed is 10 kilometers per hour and walk speed is 7 kilometers per hour.
From that you only need to know RT=D.