Question 440233: An airplane flying headwind travels the 1800 mile flying distance between two cities in 3 hours and 36 minutes. One the return flight, the distance is traveled in 3 hours. Find the air speed of the plane and the speed of the wind, assuming that both remain constant.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! An airplane flying headwind travels the 1800 mile flying distance between two cities in 3 hours and 36 minutes. One the return flight, the distance is traveled in 3 hours. Find the air speed of the plane and the speed of the wind, assuming that both remain constant.
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Against wind DATA:
distance = 1800 miles; time = (216/60) hrs ; rate = d/r = 500 mph
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With wind DATA:
distance = 1800 miles ; time = 3 hrs ; rate = d/r = 600 mph
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Equations:
p + w = 600
p - w = 500
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2p = 1100
p = 550 (speed of the plane in still air
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p + w = 600
w = 50 mph (speed of the wind current)
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Cheers,
Stan H.
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