SOLUTION: When a ball is thrown upward at a speed of 19m/s, its height s above the ground (in meters) after t seconds is given by the formula
s=19t-24.01t
find the height of the ball after
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s=19t-24.01t
find the height of the ball after
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Question 438784: When a ball is thrown upward at a speed of 19m/s, its height s above the ground (in meters) after t seconds is given by the formula
s=19t-24.01t
find the height of the ball after 3 seconds
I just can't figure out how to solve
Kim Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! When a ball is thrown upward at a speed of 19m/s, its height s above the ground (in meters) after t seconds is given by the formula
s=19t-24.01t
find the height of the ball after 3 seconds
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Sub 3 for t
s = 19*3 - 24.01*3 = -15.03 meters
Doesn't seem right, does it?
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Acutally, the equation is
s = 19t - 4.9t^2
at t=3
s = 19*3 - 4.9*9
s = 12.9 meters
