Question 433151: please help me solve this question Two cars leave towns 480 kilometers apart at the same time and travel toward each other. One car's rate is 20 kilometers per hour more than the other's. If they meet in 3 hours, what is the rate of the faster car?
Found 2 solutions by ewatrrr, solver91311:
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website!
Hi
One car's rate is 20 kilometers per hour more than the other's.
Let x and (x+20)represent the rates of the two vehicles respectively
Question states***
Two cars leave towns 480 kilometers apart at the same time and
travel toward each other, meeting in 3hrs. D = r*t
3x + 3(x+20) = 480
6x = 420
x = 70kmph. the rate of the faster car is 90kmph
CHECKING our Answer***
3hr*70kmph + 3hr*90kmph = 210km + 270km = 480km
Answer by solver91311(24713)  (Show Source):
You can put this solution on YOUR website!
If the towns are 480 km apart, by the time the two cars meet, a total of 480 km will have been traversed, part by one car and another part by the other car. If the time to the meeting is 3 hours, then the SUM of the two cars' speeds must be 480 divided by 3, or 160 km/hr. If you let  represent the speed of the faster car, then  must represent the speed of the slower car, and since the sum of their speeds is 160, we can write:
Solve for . Don't forget to express your answer in km/hr.
John
My calculator said it, I believe it, that settles it
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