SOLUTION: A MESSENGER WALKS 500 FEET IN A LARGE BUILDING FROM THE RECEPTION TO HIS DESTINATION AT THE AVERAGE SPEED FO 4 MILES PER HOURS AND RETURNS TO THE STARTING POINT AT AN AVERAGE SPEED

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Question 405869: A MESSENGER WALKS 500 FEET IN A LARGE BUILDING FROM THE RECEPTION TO HIS DESTINATION AT THE AVERAGE SPEED FO 4 MILES PER HOURS AND RETURNS TO THE STARTING POINT AT AN AVERAGE SPEED OF 3 MILES PER HOUR. WHAT IS HIS AVERAGE SPEED FOR THE ENTIRE TRIP?? HOW TO CALCULATE?
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
time = distance /speed
1 mile = 5280 feet
500 feet = 500/5280 miles
time while going = %28500%2F5280%29/4
Time while returning =%28500%2F5280%29/3
Total time = %28500%2F5280%29/4 + %28500%2F5280%29/3
Total time = 500%2F%285280%2A4%29 + 500%2F%285280%2A3%29
Total time = %28500%2A3%2B500%2A4%29%2F%285280%2A12%29
Total time = 0.055 hours
...
speed = distance / time
speed = (1000/5280) / 0.055
Average speed of total trip = 3.44 mph